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-5x^2-9x-4=-9x-4
We move all terms to the left:
-5x^2-9x-4-(-9x-4)=0
We get rid of parentheses
-5x^2-9x+9x+4-4=0
We add all the numbers together, and all the variables
-5x^2=0
a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-10}=0$
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